Results 1 to 2 of 2

Math Help - Surds

  1. #1
    Newbie
    Joined
    Nov 2008
    Posts
    4

    Surds

    So I haven't had alot of time with my surds, and I'm basically stuck on the principals, I sorta see where I'm going but then somehow its all wrong


    I'll just show a few examples, then see if someone could explain it about (if you can =) )


    2 /8 - 2 root 8




    -2/18 + 6 - 6/2

    -2 root 18 plus 6 - 6 root 2



    /27 - /3 - 2/12

    root 27 - root 3 - 2 root 12


    Family has gone away the weekend, so no one I can really ask :S


    Thanks you.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member vincisonfire's Avatar
    Joined
    Oct 2008
    From
    Sainte-Flavie
    Posts
    469
    Thanks
    2
    Awards
    1
    I don't know what you want to do but if it is to eliminate a root from the denominator you need to multiply by the conjugate.
    EG  \frac{2}{8 - 2 \sqrt{ 8 }} = \frac{2}{8 - 2 \sqrt{ 8 }} \times \frac{8 + 2 \sqrt{ 8 }}{8 + 2 \sqrt{ 8 }}

     \frac{16+4 \sqrt{8}}{64 - 16 \sqrt{ 8 }+ 16 \sqrt{ 8 } -32} =\frac{16+4 \sqrt{8}}{32}

    \frac{4+ \sqrt{4\cdot 2}}{8}=\frac{4+ \sqrt{4}\sqrt{2}}{8}= \frac{4+ 2\sqrt{2}}{8}=\frac{2+ \sqrt{2}}{4}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Help with Surds
    Posted in the Algebra Forum
    Replies: 8
    Last Post: January 5th 2012, 04:08 PM
  2. Something to do with surds?
    Posted in the Algebra Forum
    Replies: 4
    Last Post: July 11th 2011, 11:33 AM
  3. surds
    Posted in the LaTeX Help Forum
    Replies: 3
    Last Post: June 4th 2009, 05:55 PM
  4. surds
    Posted in the Algebra Forum
    Replies: 2
    Last Post: June 4th 2009, 01:30 AM
  5. surds
    Posted in the Algebra Forum
    Replies: 1
    Last Post: May 29th 2009, 05:40 AM

Search Tags


/mathhelpforum @mathhelpforum