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Math Help - Urgent: tough equation

  1. #1
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    Question Urgent: tough equation

    Hello everybody, I need some help to solve the following equation:

    (x^α)*((10-x)^(1-α)) = 10αδ with α between 0 and 1 and δ constant

    Thanks a lot!
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  2. #2
    Senior Member vincisonfire's Avatar
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     x^{\alpha} \cdot (10-x)^{1-\alpha} = 10ab

     x^{\alpha} \cdot (10-x)^{1-\alpha} \cdot (10-x)^{\alpha}= 10ab \cdot (10-x)^{\alpha}

    You know that  \alpha is form  \frac{1}{c} since  0 < \alpha < 1

     x^{\alpha} \cdot (10-x)^{1}= 10ab \cdot (10-x)^{\alpha}

     x \cdot (10-x)^{c}= 10^c a^c b^c \cdot (10-x)

    Know if you would know  \alpha you could know c and you could expand and solve the equation analytically if c would be smaller than 5.
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