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Math Help - Logritham

  1. #1
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    Red face Logritham

    Can someone help me on the following questions

    If loge (a/b) = kl/2c make a the subject of the formula. Also calculate the value of a when b = 4.16, k = 3.68, 1 = 11.41 and c = 9.23

    Thanks Alison
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by alison View Post
    Can someone help me on the following questions

    If loge (a/b) = kl/2c make a the subject of the formula. Also calculate the value of a when b = 4.16, k = 3.68, 1 = 11.41 and c = 9.23

    Thanks Alison
    The symbol for "log base e" is "ln" so I'm going to use that.

    ln(a/b) = kl/(2c) (I'm assuming the denominator is this.)

    a/b = exp[kl/(2c)] where exp is the exponential function e^

    a = b*exp[kl/(2c)]

    For the given values I get a = 40.451266618

    -Dan
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