Thread: Logritham

Originally Posted by alison

Can someone help me on the following questions

If loge (a/b) = kl/2c make a the subject of the formula. Also calculate the value of a when b = 4.16, k = 3.68, 1 = 11.41 and c = 9.23

Thanks Alison

The symbol for "log base e" is "ln" so I'm going to use that.

ln(a/b) = kl/(2c) (I'm assuming the denominator is this.)

a/b = exp[kl/(2c)] where exp is the exponential function e^

a = b*exp[kl/(2c)]

For the given values I get a = 40.451266618

-Dan