Can someone help me on the following questions If loge (a/b) = kl/2c make a the subject of the formula. Also calculate the value of a when b = 4.16, k = 3.68, 1 = 11.41 and c = 9.23 Thanks Alison

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Originally Posted by alison Can someone help me on the following questions If loge (a/b) = kl/2c make a the subject of the formula. Also calculate the value of a when b = 4.16, k = 3.68, 1 = 11.41 and c = 9.23 Thanks Alison The symbol for "log base e" is "ln" so I'm going to use that. ln(a/b) = kl/(2c) (I'm assuming the denominator is this.) a/b = exp[kl/(2c)] where exp is the exponential function e^ a = b*exp[kl/(2c)] For the given values I get a = 40.451266618 -Dan

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