I would greatly appreciate if someone could help me on this one, thank you so much:
Solve for x to eight decimal places if
2^(2x – 1) = 3^(x-2)
Substitute your x value answer
back into original and show that it
will make each side equal.
I would greatly appreciate if someone could help me on this one, thank you so much:
Solve for x to eight decimal places if
2^(2x – 1) = 3^(x-2)
Substitute your x value answer
back into original and show that it
will make each side equal.
Hello!
Note that $\displaystyle 2^{2x-1}=3^{x-1}\implies 4^x 2^{-1}=3^x 3^{-1}\implies\left(\tfrac{4}{3}\right)^x=\tfrac{2}{3} \implies x=\frac{\ln\left(\tfrac{2}{3}\right)}{\ln\left(\tf rac{4}{3}\right)}$
Now you can plug this into your calculator and get an approximation to 8 decimal places.
--Chris