1. -15x^2/20x 2. (3x)^2/4xy * 16y/36x 3. x^2+3/x^2 + x-1/5
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1. -15x^2/20x = -3x/4 ( Just simplify terms ) 2. 3x^2/4xy multiply 16y/36x 48yx^2 / 144yx^2 ( Multiply the two terms first ) 1 / 3 ( Then simplify ) Base on the help provided hope you will be able to answer question 3
Originally Posted by tester85 1. -15x^2/20x = -3x/4 ( Just simplify terms ) 2. 3x^2/4xy multiply 16y/36x 48yx^2 / 144yx^2 ( Multiply the two terms first ) 1 / 3 ( Then simplify ) Base on the help provided hope you will be able to answer question 3 Wouldn't 1 be -3x^2/4x?
Originally Posted by william Wouldn't 1 be -3x^2/4x? $\displaystyle -\frac{3x^2}{4x}=-\frac{3x\cdot x}{4x}=-\frac{3x}{4} \cdot \frac{x}{x}=-\frac{3x}{4}\cdot 1=-\frac{3x}{4}$
Originally Posted by tester85 1. -15x^2/20x = -3x/4 ( Just simplify terms ) 2. 3x^2/4xy multiply 16y/36x 48yx^2 / 144yx^2 ( Multiply the two terms first ) 1 / 3 ( Then simplify ) Base on the help provided hope you will be able to answer question 3 Are you suggesting, for #2, that 1/3 is the most simplified form and the xy^2 simply gets canceled out?
Originally Posted by william Are you suggesting, for #2, that 1/3 is the most simplified form and the xy^2 simply gets canceled out? yes, $\displaystyle =\frac{3x^2}{4xy}\times\frac{16y}{36x}$ $\displaystyle =\frac{48x^2y}{144x^2y}$ $\displaystyle =\frac{1}{3}.\frac{x^2y}{x^2y}$ $\displaystyle =\frac{1}{3}$ got it??? Now finish #3 yourself.
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