# Thread: simplify

1. ## simplify

1. -15x^2/20x

2. (3x)^2/4xy * 16y/36x

3. x^2+3/x^2 + x-1/5

2. 1. -15x^2/20x = -3x/4 ( Just simplify terms )

2. 3x^2/4xy multiply 16y/36x
48yx^2 / 144yx^2 ( Multiply the two terms first )
1 / 3 ( Then simplify )

Base on the help provided hope you will be able to answer question 3

3. Originally Posted by tester85
1. -15x^2/20x = -3x/4 ( Just simplify terms )

2. 3x^2/4xy multiply 16y/36x
48yx^2 / 144yx^2 ( Multiply the two terms first )
1 / 3 ( Then simplify )

Base on the help provided hope you will be able to answer question 3
Wouldn't 1 be -3x^2/4x?

4. Originally Posted by william
Wouldn't 1 be -3x^2/4x?
$-\frac{3x^2}{4x}=-\frac{3x\cdot x}{4x}=-\frac{3x}{4} \cdot \frac{x}{x}=-\frac{3x}{4}\cdot 1=-\frac{3x}{4}$

5. Originally Posted by tester85
1. -15x^2/20x = -3x/4 ( Just simplify terms )

2. 3x^2/4xy multiply 16y/36x
48yx^2 / 144yx^2 ( Multiply the two terms first )
1 / 3 ( Then simplify )

Base on the help provided hope you will be able to answer question 3
Are you suggesting, for #2, that 1/3 is the most simplified form and the xy^2 simply gets canceled out?

6. Originally Posted by william
Are you suggesting, for #2, that 1/3 is the most simplified form and the xy^2 simply gets canceled out?
yes,

$=\frac{3x^2}{4xy}\times\frac{16y}{36x}$

$=\frac{48x^2y}{144x^2y}$

$=\frac{1}{3}.\frac{x^2y}{x^2y}$

$=\frac{1}{3}$

got it??? Now finish #3 yourself.