How would you solve (1/5)² - 5 = 0
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Originally Posted by JennRevina How would you solve (1/5)² - 5 = 0 uhhh ... $\displaystyle \left(\frac{1}{5}\right)^2 - 5 \neq 0$ did you miss a variable somewhere?
Oh, had a typo. Here's the question; (1/5)x² - 5 = 0 Yeah, sorry.
multiply by 5 ... $\displaystyle x^2 - 25 = 0$ can you finish from here?
Mhm. Thanks. I guess I just wasnt thinking. =/
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