I'd like to know the relation between log scale and ln.
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Hello, Originally Posted by E080014 I'd like to know the relation between log scale and ln. Actually, $\displaystyle \ln(x)=\log_e(x)$ and for any $\displaystyle a>1$, we have : $\displaystyle \log_a(x)=\frac{\ln(x)}{\ln(a)}$
Originally Posted by Moo Hello, Actually, $\displaystyle \ln(x)=\log_e(x)$ and for any $\displaystyle a>1$, we have : $\displaystyle \log_a(x)=\frac{\ln(x)}{\ln(a)}$ Hello Moo, bon soir, in my opinion it is possible to expand your statement to: "...and for any $\displaystyle a>0~\wedge~a \ne 1$, we have : $\displaystyle \log_a(x)=\frac{\ln(x)}{\ln(a)}$ "
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