# Math Help - logrithms

1. ## logrithms

I'd like to know the relation between log scale and ln.

2. Hello,
Originally Posted by E080014
I'd like to know the relation between log scale and ln.
Actually, $\ln(x)=\log_e(x)$

and for any $a>1$, we have :
$\log_a(x)=\frac{\ln(x)}{\ln(a)}$

3. Originally Posted by Moo
Hello,

Actually, $\ln(x)=\log_e(x)$

and for any $a>1$, we have :
$\log_a(x)=\frac{\ln(x)}{\ln(a)}$
Hello Moo, bon soir,

in my opinion it is possible to expand your statement to:

"...and for any $a>0~\wedge~a \ne 1$, we have :
$\log_a(x)=\frac{\ln(x)}{\ln(a)}$ "