$\displaystyle T(z) = \frac{z}{2-z}$
$\displaystyle S^{-1}(z) = 4\frac{z-1}{z+4}$
Solve:
$\displaystyle L(z) = S^{-1}(T(z))$
Can someone show me the steps? I know to plug in for z but I can't seem to do it the right way...
Repost, sorry I thought mine was wrong and Moo wrote it more nicely by the way.
$\displaystyle L(z) = S^{-1}(T(z))=S^{-1}\left(\frac{z}{2-z}\right)=4\frac{\frac{z}{2-z}-1}{\frac{z}{2-z}+4}=-\frac{8 (-1+z)}{-8+3 z}$
$\displaystyle z\ne 2\,\text{and}\, \frac 83$