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Math Help - All help is GREATLY appreciated!!! :)

  1. #1
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    All help is GREATLY appreciated!!! :)

    Solve for x to eight decimal places if

    2^(2x – 1) = 3^(x-2)

    Substitute your x value answer
    back into original and show that it
    will make each side equal.
    Last edited by Alesa'7; November 6th 2008 at 06:54 PM.
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  2. #2
    Senior Member vincisonfire's Avatar
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    2(2x  1) = 3(x-2)
    4x  2 = 3x-6
    x = -4
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  3. #3
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    Oh I am sorry those numbers in parenthesis are suppost to be exponets (2x-1) and (x-2) are exponets, i am so sry..
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  4. #4
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    Quote Originally Posted by Alesa'7 View Post
    Oh I am sorry those numbers in parenthesis are suppost to be exponets (2x-1) and (x-2) are exponets, i am so sry..
    2^{2x-1} = 3^{x-2} \Rightarrow \log_{10} 2^{2x-1} = \log_{10} 3^{x-2} \Rightarrow (2x - 1) \log_{10} 2 = (x - 2) \log_{10} 3.

    This has the form a(2x-1) = b(x - 2). Expand and make x the subject. Then use a calculator to get the required approximate value.
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  5. #5
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    Response to your comment.

    yea, if you would have read then you would see that I had written it incorrectly , and I had already thanked him, and others who are Trying to Help, would see that it had already been replied to and then would move on and not bother.. Soo.. I rewrote the question showing that it hadnt in fact been answered at all, (correctly any way).as of now, by the way, it still hasnt been correctly solved.
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