Solve for x to eight decimal places if
2^(2x – 1) = 3^(x-2)
Substitute your x value answer
back into original and show that it
will make each side equal.
$\displaystyle 2^{2x-1} = 3^{x-2} \Rightarrow \log_{10} 2^{2x-1} = \log_{10} 3^{x-2} \Rightarrow (2x - 1) \log_{10} 2 = (x - 2) \log_{10} 3$.
This has the form $\displaystyle a(2x-1) = b(x - 2)$. Expand and make x the subject. Then use a calculator to get the required approximate value.
yea, if you would have read then you would see that I had written it incorrectly , and I had already thanked him, and others who are Trying to Help, would see that it had already been replied to and then would move on and not bother.. Soo.. I rewrote the question showing that it hadnt in fact been answered at all, (correctly any way).as of now, by the way, it still hasnt been correctly solved.