Thread: All help is GREATLY appreciated!!! :)

1. All help is GREATLY appreciated!!! :)

Solve for x to eight decimal places if

2^(2x – 1) = 3^(x-2)

back into original and show that it
will make each side equal.

2. $2(2x – 1) = 3(x-2)$
$4x – 2 = 3x-6$
$x = -4$

3. Oh I am sorry those numbers in parenthesis are suppost to be exponets (2x-1) and (x-2) are exponets, i am so sry..

4. Originally Posted by Alesa'7
Oh I am sorry those numbers in parenthesis are suppost to be exponets (2x-1) and (x-2) are exponets, i am so sry..
$2^{2x-1} = 3^{x-2} \Rightarrow \log_{10} 2^{2x-1} = \log_{10} 3^{x-2} \Rightarrow (2x - 1) \log_{10} 2 = (x - 2) \log_{10} 3$.

This has the form $a(2x-1) = b(x - 2)$. Expand and make x the subject. Then use a calculator to get the required approximate value.