Hello,

hoping some maths genius on here can help me out!

$\displaystyle \frac{2}{x-3} + \frac{1}{x+2} = \frac{7}{x^2-x-6} $

i know that i have to factor the bottom $\displaystyle \frac{2}{x-3} + \frac{1}{x+2} = \frac{7}{(x+2) (x-3)} $ were do i go from here?