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Math Help - Factorizing & Simplifying

  1. #1
    Pink_Apple
    Guest

    Factorizing & Simplifying

    Hello peeps!

    I know how to simplify simple equations...like 8/3(x-1) + 2/x-1 you just multiply x-1 with 3 and multiply 2 with 3...but how about simplifying harder question like...

    4x/ 3x^2+7x-6 - x/3x^2-14x+8


    I tried to factorize the first denomenator it's (3x-6)(x-1)..right?

    I dunno how to factorize the second deno..and im not sure how to continue simplifying..i think ill know if i knew how to factorize the second deno..

    Thanks.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Pink_Apple View Post
    Hello peeps!

    I know how to simplify simple equations...like 8/3(x-1) + 2/x-1 you just multiply x-1 with 3 and multiply 2 with 3...but how about simplifying harder question like...

    4x/ 3x^2+7x-6 - x/3x^2-14x+8


    I tried to factorize the first denomenator it's (3x-6)(x-1)..right?

    I dunno how to factorize the second deno..and im not sure how to continue simplifying..i think ill know if i knew how to factorize the second deno..

    Thanks.
    The first think you need to do is learn to use brackets to make
    the expressions unambiguous.

    Do you mean - simplify:

    4x/(3x^2+7x-6) - x/(3x^2-14x+8)

    Then the first denominator does not factorise as you suggest as:

    (3x-6)(x-1)=3x^2-7x+6.

    In fact:

    3x^2+7x-6=(x+3)(3x-2)

    and:

    3x^2-14x+8=(x-4)(3x-2).

    This suggests you can start your simplification by taking out the common
    factor 1/(3x-2).

    RonL
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