Simplify: {(2x^2y)/( 3xy^3)}^2
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Originally Posted by Mccoy31 Simplify: {(2x^2y)/( 3xy^3)}^2 $\displaystyle \left(\frac{2x^2y}{3xy^3}\right)^2=\left(\frac{4x^ 4y^2}{9x^2y^6}\right)=\frac{4x^2}{9y^4}$
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