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Math Help - Algebra help needed!

  1. #1
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    Algebra help needed!

    Find the smallest natural number, x, for which 3 divides x, 5 divides (x+1) and 7 divides (x+2).

    I don't seem to be able to solve this please help
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  2. #2
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    Norfolk, england.
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    If i've understood your question correctly, we have:

    x/3, x+1/5, and x+2/7

    If thisis right then we can just simplify the expressions x+1/5 can go to x/4, and x+2/7 can go to x/5

    therefore we want a number that is divisable by 3,4, and 5. The the easiest way to find with these number is to multiply them, 3*4 = 12

    12*5 = 60.

    So i think 60 is your answer, however i'm not sure that that was your question, it depends by what you mean by '3 divides x' etc.

    Anyways hope this helped.
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  3. #3
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    The question does ask x/3, x+1/5, and x+2/7. The method you suggested does not work

    X+1/5 is not the same as X/4

    Let x be 6

    6+1/5 = 1.4
    6/4 = 1.5


    6+1/5 6/4

    1.4 1.5
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