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Math Help - confuzing polynomials

  1. #1
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    confuzing polynomials

    1. Divide 6 x into x2 + 4x 16.


    2. Divide 2x 1 into 4x4 5x2 + 2x + 4.

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  2. #2
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    Quote Originally Posted by 14041471 View Post
    1. Divide 6 x into x2 + 4x 16.


    2. Divide 2x 1 into 4x4 5x2 + 2x + 4.
    Read this: Polynomial Long Division
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    Quote Originally Posted by 14041471 View Post
    please give me the awnser to this question.
    Divide 2x 1 into 4x4 5x2 + 2x + 4
    2x^3+x^2-2x+\frac{4}{2x-1}
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    thanks alot

    one other thing, can you simplify this for me
    (x^3 + x^2 + 6x) - (2^3 + 2^2 + 6(2))
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    Quote Originally Posted by 14041471 View Post
    one other thing, can you simplify this for me
    (x^3 + x^2 + 6x) - (2^3 + 2^2 + 6(2))
    Did you leave some variables out, or was that the way the problem was written?

    (x^3+x^2+6x)-(2^3+2^2+6(2))

    x^3+x^2+6x-8-4-12

    x^3+x^2+6x-24
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    reply

    thanks yeah that was the way it was written.
    one last thing youve been great help.

    A company estimates that it costs 0.03x2 + 4x + 1000 dollars to produce x units of a product. Find an expression for the average cost per unit.

    I think i need to divide something to get the RATE
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    Quote Originally Posted by 14041471 View Post
    thanks yeah that was the way it was written.
    one last thing youve been great help.

    A company estimates that it costs 0.03x2 + 4x + 1000 dollars to produce x units of a product. Find an expression for the average cost per unit.

    I think i need to divide something to get the RATE
    Increase your font size when you post. I'm gettin old and can't see as well as I used to.

    To find the average cost per unit, divide total dollars by number of units.

    Average cost per unit = \frac{0.03x^2+4x+1000}{x}
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    thanks

    thanks, is that in its simplest form?
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    Quote Originally Posted by 14041471 View Post
    thanks, is that in its simplest form?
    It would be for me. However, you could write the quotient like this:

    Average cost per unit = 0.03x+4 +\frac{1000}{x}
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