Okay I have established that you multiply by the denomonator after changing it's sign. For example 3-2i (3-2i)(5-i) ____ = _________ 5+i (5+i)(5-i) My question is how do I solve 2+i ____ i
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Originally Posted by KeiaBlake Okay I have established that you multiply by the denomonator after changing it's sign. For example 3-2i (3-2i)(5-i) ____ = _________ 5+i (5+i)(5-i) My question is how do I solve 2+i ____ i Just multiply the numerator and denominator by i: $\displaystyle \frac{2+i}{i}=\frac{2i+i^2}{i^2}=\frac{2i-1}{-1}=\color{red}\boxed{1-2i}$ Does this make sense? --Chris
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