Okay I have established that you multiply by the denomonator after changing it's sign. For example 3-2i (3-2i)(5-i) ____ = _________ 5+i (5+i)(5-i) My question is how do I solve 2+i ____ i
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Originally Posted by KeiaBlake Okay I have established that you multiply by the denomonator after changing it's sign. For example 3-2i (3-2i)(5-i) ____ = _________ 5+i (5+i)(5-i) My question is how do I solve 2+i ____ i Just multiply the numerator and denominator by i: Does this make sense? --Chris
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