Okay I have established that you multiply by the denomonator after changing it's sign. For example

3-2i (3-2i)(5-i)

____ = _________

5+i (5+i)(5-i)

My question is how do I solve

2+i

____

i

Printable View

- Nov 4th 2008, 09:29 PMKeiaBlakeDividing Complex Numbers
Okay I have established that you multiply by the denomonator after changing it's sign. For example

3-2i (3-2i)(5-i)

____ = _________

5+i (5+i)(5-i)

My question is how do I solve

2+i

____

i - Nov 4th 2008, 09:33 PMChris L T521