Dividing Complex Numbers

Okay I have established that you multiply by the denomonator after changing it's sign. For example
3-2i (3-2i)(5-i)
____ = _________
5+i (5+i)(5-i)



My question is how do I solve

2+i
____
i

Quote:

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Originally Posted by KeiaBlake

Okay I have established that you multiply by the denomonator after changing it's sign. For example
3-2i (3-2i)(5-i)
____ = _________
5+i (5+i)(5-i)



My question is how do I solve

2+i
____
i

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Just multiply the numerator and denominator by i:



Does this make sense?

--Chris