Results 1 to 5 of 5

Math Help - will someone please verify the solution to my problems

  1. #1
    Senior Member euclid2's Avatar
    Joined
    May 2008
    From
    Ottawa, Canada
    Posts
    400
    Awards
    1

    will someone please verify the solution to my problems

    I have done the work, but i need someone to verify if they are correct.

    Simplify.

    a)4x^2y^5/x^4y^2 = 4x^2y^3


    b)3xy/9x^2-12x = 3y/3x-4


    c) 4x^2-20x/x+3 * 4x^2-1/2x^2-9x-5 = 4x^2(2x-1)/(x+3)


    d) 4x+1/3x-5 + 2x/12x-20 = (9x+2)/(6x-10)


    e) how would i simplify 3x-1/x^2+4x+3 - x+6/2x^2+7x+1
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie Black Kawairothlite's Avatar
    Joined
    Oct 2008
    Posts
    21
    a)missing a (-)

    \frac{{4x^2y^5}}{{x^4y^2}}=4x^2y^5x^{-4}y^{-2}=4x^{-2}y^3

    b) err...

    \frac{{3xy}}{{9x^2-12x}}=\frac{{3xy}}{{3x(3x-4)}}=\frac{{y}}{{3x-4}}

    c) this is what i did

    \frac{{4x^2-20x}}{{x+3}}*\frac{{4x^2-1}}{{2x^2-9x-5)}}=\frac{{4x(x-5)}}{{x+3}}*\frac{{4x^2-1}}{{(2x+1)(x-5)}}=\frac{{4x}}{{x+3}}*\frac{{4x^2-1}}{{(2x+1)}}

    continue

    d) something is wrong...

    \frac{{4x+1}}{{3x-5}}+\frac{{2x}}{{12x-20)}}=\frac{{4x+1}}{{3x-5}}+\frac{{x}}{{6x-10)}}=\frac{{4x+1}}{{3x-5}}+\frac{{x}}{{2(3x-5)}}= \frac{{4x+1+2x}}{{3x-5}}=\frac{{6x+1}}{{3x-5}}

    e) jeez too long

    you should do the algebraic sum as usual

    \frac{{a(x)}}{{b(x)}}-\frac{{c(x)}}{{d(x)}}=\frac{{a(x)d(x)-b(x)c(x)}}{{b(x)d(x)}}
    Last edited by Black Kawairothlite; November 4th 2008 at 06:56 PM. Reason: hehe...
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member euclid2's Avatar
    Joined
    May 2008
    From
    Ottawa, Canada
    Posts
    400
    Awards
    1
    Quote Originally Posted by Black Kawairothlite View Post
    a)missing a (-)

    \frac{{4x^2y^5}}{{x^4y^2}}=4x^2y^5x^{-4}y^{-2}=4x^{-2}y^3
    Oh, i see!
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member euclid2's Avatar
    Joined
    May 2008
    From
    Ottawa, Canada
    Posts
    400
    Awards
    1
    Quote Originally Posted by Black Kawairothlite View Post
    a)missing a (-)

    \frac{{4x^2y^5}}{{x^4y^2}}=4x^2y^5x^{-4}y^{-2}=4x^{-2}y^3

    b) err...

    \frac{{3xy}}{{9x^2-12x}}=\frac{{3xy}}{{3x(3x-4)}}=\frac{{y}}{{3x-4}}
    Absolutely, I forgot to cancel that 3 out by accident
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Senior Member euclid2's Avatar
    Joined
    May 2008
    From
    Ottawa, Canada
    Posts
    400
    Awards
    1
    Quote Originally Posted by Black Kawairothlite View Post
    a)missing a (-)

    \frac{{4x^2y^5}}{{x^4y^2}}=4x^2y^5x^{-4}y^{-2}=4x^{-2}y^3

    b) err...

    \frac{{3xy}}{{9x^2-12x}}=\frac{{3xy}}{{3x(3x-4)}}=\frac{{y}}{{3x-4}}

    c) this is what i did

    \frac{{4x^2-20x}}{{x+3}}*\frac{{4x^2-1}}{{2x^2-9x-5)}}=\frac{{4x(x-5)}}{{x+3}}*\frac{{4x^2-1}}{{(2x+1)(x-5)}}=\frac{{4x}}{{x+3}}*\frac{{4x^2-1}}{{(2x+1)}}

    continue
    I appreciate the help.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Verify Solution
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: October 5th 2011, 07:43 AM
  2. please verify i have the correct solution
    Posted in the Advanced Statistics Forum
    Replies: 2
    Last Post: March 6th 2011, 03:17 PM
  3. Verify a solution
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: February 9th 2010, 10:51 PM
  4. Homework Help/Verify solution
    Posted in the Algebra Forum
    Replies: 2
    Last Post: December 10th 2007, 02:28 AM
  5. Verify solution of equation
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: November 25th 2007, 06:15 AM

Search Tags


/mathhelpforum @mathhelpforum