hey can someone run me through the steps to solve: 2^2x - 2^(x+3) + 2^4 = 0 thanks much appreciated
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Originally Posted by seanybeaver hey can someone run me through the steps to solve: 2^2x - 2^(x+3) + 2^4 = 0 thanks much appreciated $\displaystyle \Rightarrow 2^{2x} - 8 (2^x) + 16 = 0$. Substitute $\displaystyle w = 2^x$: $\displaystyle w^2 - 8w + 16 = 0$. Solve for w. Then solve $\displaystyle 2^x = w$ for x.
thanks a lot
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