How do I factorize x^4-3x^3-22x^2+12x+72
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Originally Posted by Mathsnewbie How do I factorize x^4-3x^3-22x^2+12x+72 = x^4- 2x^3 - x^3 + 2x^2- 24x^2+ 48x- 36x+ 72 = (x-2)(x^3-x^2-24x-36) = (x-2)(x+2)(x^2-9x+18) = (x-2)(x+2)(x-3)(x-6) the last term generally has the soln. as a factor as 72 here
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