6/5y-5=7
To expand on TomCat's post is the question:
(6/5)y - 5 = 7
or
6/(5y) - 5 = 7?
I'll solve both.
(6/5)y - 5 = 7
(6/5)y - 5 + 5 = 7 + 5
(6/5)y = 12
5*(6/5)y = 5*12
6y = 60
6y/6 = 60/6
y = 10.
Now the other one:
6/(5y) - 5 = 7
6/(5y) - 5 + 5 = 7 + 5
6/(5y) = 12
Multiply both sides by 5y to remove the fraction. Remember that y cannot be 0.
(5y)*6/(5y) = (5y)*12
6 = 60y
6/60 = 60y/60
y = 1/10 (y is not zero, so we're)
-Dan