log4 2+ log4 8=? Thank you
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Originally Posted by beachbunny619 log4 2+ log4 8=? Thank you The logarithms have the same base. Therefore you can use the property: $\displaystyle \log_b(x)+\log_b(y)=\log_b(x \cdot y)$ With your question you have: $\displaystyle \log_4(2)+\log_4(8)=\log_4(2 \cdot 8) = \log_4(16) = \log_4(4^2) = 2$
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