(x+y)^2-(9xy-6x^2)=

how do you work this problem?

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- Nov 3rd 2008, 04:14 PMabner80binomials
(x+y)^2-(9xy-6x^2)=

how do you work this problem? - Nov 3rd 2008, 04:17 PMbadgerigar
Expand the brackets and collect like terms. If you cannot remember the formula for $\displaystyle (x+y)^2$ then multiply out (x+y)(x+y).

- Nov 4th 2008, 05:36 PMabner80More help
Okay so I get x^2 + xy + yx +y^2 is this right and what can I do with the second set of terms?