$\displaystyle \frac{x + y - (x^2 + y^2)}{x + y } $ dont know were to start
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Originally Posted by Tweety $\displaystyle \frac{x + y - (x^2 + y^2)}{x + y } $ dont know were to start You might change it to this, but I'm not sure if that's a simplification. $\displaystyle \frac{x+y}{x+y}-\frac{x^2+y^2}{x+y}=1-\frac{x^2+y^2}{x+y}$
Originally Posted by masters You might change it to this, but I'm not sure if that's a simplification. $\displaystyle \frac{x+y}{x+y}-\frac{x^2+y^2}{x+y}=1-\frac{x^2+y^2}{x+y}$ Hi, thanks for replying but apparently the answer is $\displaystyle \frac{2xy}{x +y} $ I don't know how to get to this.
Use polynomial long division.
Hello, Complete a square : $\displaystyle x^2+y^2=x^2+y^2+2xy-2xy=(x+y)^2-2xy$ So we have : $\displaystyle \frac{(x+y)-(x+y)^2+2xy}{x+y}=1-(x+y)+\frac{2xy}{x+y}$
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