$\displaystyle \frac{x + y - (x^2 + y^2)}{x + y } $

dont know were to start

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- Nov 3rd 2008, 10:57 AMTweetysimplifying expression help.
$\displaystyle \frac{x + y - (x^2 + y^2)}{x + y } $

dont know were to start - Nov 3rd 2008, 12:22 PMmasters
- Nov 3rd 2008, 12:25 PMTweety
- Nov 8th 2008, 08:20 AMChop Suey
Use polynomial long division.

- Nov 8th 2008, 08:23 AMMoo
Hello,

Complete a square :

$\displaystyle x^2+y^2=x^2+y^2+2xy-2xy=(x+y)^2-2xy$

So we have :

$\displaystyle \frac{(x+y)-(x+y)^2+2xy}{x+y}=1-(x+y)+\frac{2xy}{x+y}$

(Tongueout)