Solve the following system of equations using the elimination method

3x-9y=10 (1)

4x+y=7 (2)

I have completed this question, but I would like someone to look over it to make sure that I did the right thing, because it does not look like the right answer to me. Any help or comments would be appreciated.

Thanks!

My Answer:

3x-9y=10 (1)

4x+y=7 (2)

By elimination:

Take equation (2) and multiply by 9

Thus, (2) x 9 gives you 36x-9y = 63 (3)

Add equation 3 to 1

Which gives you 39x = 73 ... divide both sides by 39 and x= 73/39 or 1.87

Substitute x (1.87) into Equation #1 to find y:

3(73/39)-9y=10

..This is where I get confused.