can i solve the system

x^n = 12

n^x = 4

i keep running into problems like n=1 and x= (LN(4))/0

(wew... don't let the perfecthacker see that)

or would the values just be undifind??

dan

Printable View

- Sep 21st 2006, 05:07 PMdansystem
can i solve the system

x^n = 12

n^x = 4

i keep running into problems like n=1 and x= (LN(4))/0

(wew... don't let the perfecthacker see that)

or would the values just be undifind??

dan - Sep 21st 2006, 05:20 PMQuick
- Sep 21st 2006, 05:27 PMtopsquark
The best I can do for you is this:

From the second equation, if we take ln of both sides:

ln(n^x) = ln(4)

x ln(n) = ln(4)

x = ln(4)/ln(n)

Insert this into the first equation:

[ln(4)/ln(n)]^n = 12

This is, at least, an equation in one variable. Supposedly you can solve this numerically.

-Dan - Sep 21st 2006, 05:52 PMThePerfectHacker
I belive you can use Lambert function on,

(though I did not try it) - Sep 21st 2006, 08:22 PMCaptainBlack
- Sep 21st 2006, 08:25 PMCaptainBlack
- Sep 22nd 2006, 06:53 AMThePerfectHacker
- Sep 22nd 2006, 04:38 PMdan
- Sep 22nd 2006, 08:52 PMCaptainBlack
- Sep 23rd 2006, 02:19 PMdan