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Math Help - 6th Grade word problem

  1. #1
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    6th Grade word problem

    My son dumped this one on me and I haven't a clue and my husband isn't home to help.

    "Artie placed a "5" at the right hand end (unit's place) of a 3-digit number. That increased the value of the number by 3074. What was the original number?"

    Thanks in advance for any help..
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by mnC5 View Post
    My son dumped this one on me and I haven't a clue and my husband isn't home to help.

    "Artie placed a "5" at the right hand end (unit's place) of a 3-digit number. That increased the value of the number by 3074. What was the original number?"

    Thanks in advance for any help..
    You have a 3 digit number. So there are 1's , 10's, and 100's.

    Let x;y;z denote integer placeholders.

    (1000x + 100y + 10z + 5) - (100x + 10y + z) = 3074

    10(100x + 10y + z) - (100x + 10y + z) = 3074 - 5

    9(100x + 10y + z) = 3069

    (100x + 10y + z) = 341

    So our original number was 341.

    Artie concatenated a 5 which made it 3415

    The difference between 3415 and 341 must give us 3074, and it does, so we have solved the problem
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  3. #3
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    LOL, so well put I understood it.
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  4. #4
    Bar0n janvdl's Avatar
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    Quote Originally Posted by mnC5 View Post
    LOL, so well put I understood it.
    Glad we could help.
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