• Nov 1st 2008, 10:56 AM
mnC5
My son dumped this one on me and I haven't a clue(Headbang) and my husband isn't home to help.

"Artie placed a "5" at the right hand end (unit's place) of a 3-digit number. That increased the value of the number by 3074. What was the original number?"

Thanks in advance for any help..
• Nov 1st 2008, 11:27 AM
janvdl
Quote:

Originally Posted by mnC5
My son dumped this one on me and I haven't a clue(Headbang) and my husband isn't home to help.

"Artie placed a "5" at the right hand end (unit's place) of a 3-digit number. That increased the value of the number by 3074. What was the original number?"

Thanks in advance for any help..

You have a 3 digit number. So there are 1's , 10's, and 100's.

Let x;y;z denote integer placeholders.

(1000x + 100y + 10z + 5) - (100x + 10y + z) = 3074

10(100x + 10y + z) - (100x + 10y + z) = 3074 - 5

9(100x + 10y + z) = 3069

(100x + 10y + z) = 341

So our original number was 341.

Artie concatenated a 5 which made it 3415

The difference between 3415 and 341 must give us 3074, and it does, so we have solved the problem (Happy)
• Nov 1st 2008, 11:43 AM
mnC5
LOL, so well put I understood it.(Rofl)
• Nov 1st 2008, 11:45 AM
janvdl
Quote:

Originally Posted by mnC5
LOL, so well put I understood it.(Rofl)