1. ## factors

Hi,

This is one of my homework questiosn and I have no idea how to solve it...

it says: consider m= 2^9 * 17^3 * 67^2. without elaborate calculation, tell which of the following could NOT be factors of m.

A. 2^8 * 7
B. 2^10 * 17^2 * 67
C. 2^8 * 17^2 * 67^2
D. 34^3
E. 134^2

2. Originally Posted by Pinky&The Brain
Hi,

This is one of my homework questiosn and I have no idea how to solve it...

it says: consider m= 2^9 * 17^3 * 67^2. without elaborate calculation, tell which of the following could NOT be factors of m.

A. 2^8 * 7
B. 2^10 * 17^2 * 67
C. 2^8 * 17^2 * 67^2
D. 34^3
E. 134^2
B.
Because 2^10 and the number is 2^9 it is more than it.

3. thanks fpr your help, but i do not understand that technique of how to solve it

4. Originally Posted by Pinky&The Brain
thanks fpr your help, but i do not understand that technique of how to solve it
you're not alone

5. Originally Posted by Pinky&The Brain
thanks fpr your help, but i do not understand that technique of how to solve it
Consider a smaller number, say 12.

12 = 2^2 * 3

Is 9 a factor of 12? No. Why not?

9 = 3^2

9 contains 2 factors of 3 and 12 contains only 1. Any factor of 12 would have to have at most 2 2's and at most 1 3.

-Dan

6. Originally Posted by topsquark
Consider a smaller number, say 12.

12 = 2^2 * 3

Is 9 a factor of 12? No. Why not?

9 = 3^2

9 contains 2 factors of 3 and 12 contains only 1. Any factor of 12 would have to have at most 2 2's and at most 1 3.

-Dan
Now I see, tanx

7. thank you very much for your help.... i get it now...