1. ## simplify check #2

$
\frac {x^4+x^2y^2+y^4}{x^3-y^3} \div \frac{x^2-xy+y^2}{x-y}
$

$
\frac {x^4+x^2y^2+y^4}{(x-y)(x^2+xy+y^2)} \cdot \frac{x-y}{x^2-xy+y^2}
$

$
\frac {x^2+xy+y^2}{x^2+xy+y^2}
$

$
= 1
$

this correcT?

2. Originally Posted by jvignacio
$
\frac {x^4+x^2y^2+y^4}{x^3-y^3} \div \frac{x^2-xy+y^2}{x-y}
$

$
\frac {x^4+x^2y^2+y^4}{(x-y)(x^2+xy+y^2)} \cdot \frac{x-y}{x^2-xy+y^2}
$

$
\frac {x^2+xy+y^2}{x^2+xy+y^2}
$

$
= 1
$

this correcT?
Yes, but again it would help if you provided more of your working (like the link between the second and third lines)

CB

3. Originally Posted by CaptainBlack
Yes, but again it would help if you provided more of your working (like the link between the second and third lines)

CB
that link is just cancelling out terms

4. Originally Posted by jvignacio
that link is just cancelling out terms
Except it requires that you know how $x^4+x^2y^2+y^4$ factorises.

CB

5. Originally Posted by jvignacio
that link is just cancelling out terms
There's a very good reason why CaptainB is asking to see your working .....

Teacher: Simplify 16/64.
Student: 1/4.
Teacher: Correct. How did you do that?
Student: I just cancelled numbers
Teacher: Mind showing me.
Student: *Grumble* OK ....... $\frac{1 \not{6}}{\not{6}4} = \frac{1}{4}$. We cool now ....?

Do you see the moral of the story?

6. Originally Posted by mr fantastic
There's a very good reason why CaptainB is asking to see your working .....

Teacher: Simplify 16/64.
Student: 1/4.
Teacher: Correct. How did you do that?
Student: I just cancelled numbers
Teacher: Mind showing me.
Student: *Grumble* OK ....... $\frac{1 \not{6}}{\not{6}4} = \frac{1}{4}$. We cool now ....?

Do you see the moral of the story?
Yea i see it. guess i wasnt suppose to cancel out that way but it worked anyway?