$\displaystyle 8x - 2xy -xy^2 = 0 $ $\displaystyle x(-y-4)(y-2) = 0 $ correct? thanks
Follow Math Help Forum on Facebook and Google+
Originally Posted by jvignacio $\displaystyle 8x - 2xy -xy^2 = 0 $ $\displaystyle x(-y-4)(y-2) = 0 $ correct? thanks Yes, but you can check this yourself by multiplying out the factorisation. CB
View Tag Cloud