factorizing

**jvignacio** · October 31st 2008, 11:33 PM

$(2x+1)^2 + x(2+4x) = 0$

then i expanded and collected like terms and got

$8x^2+6x+1 = 0$

then i was having problems factorizing this expression.any help?

**Peritus** · November 1st 2008, 12:17 AM

you don't need to expand anything:

$\begin{gathered} \left( {2x + 1} \right)^2 + x\left( {2 + 4x} \right) = 0 \hfill \\ \Leftrightarrow \left( {2x + 1} \right)^2 + 2x\left( {2x + 1} \right) = 0 \hfill \\ \Leftrightarrow \left( {2x + 1} \right)\left( {4x + 1} \right) = 0 \hfill \\ \end{gathered} $

**jvignacio** · November 1st 2008, 12:24 AM

Originally Posted by Peritus

you don't need to expand anything:

$\begin{gathered} \left( {2x + 1} \right)^2 + x\left( {2 + 4x} \right) = 0 \hfill \\ \Leftrightarrow \left( {2x + 1} \right)^2 + 2x\left( {2x + 1} \right) = 0 \hfill \\ \Leftrightarrow \left( {2x + 1} \right)\left( {4x + 1} \right) = 0 \hfill \\ \end{gathered} $

yes yes i had it right, just made a silly mistake... thanks for that!

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