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Math Help - factorizing

  1. #1
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    factorizing

    (2x+1)^2 + x(2+4x) = 0

    then i expanded and collected like terms and got

    8x^2+6x+1 = 0

    then i was having problems factorizing this expression.any help?
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  2. #2
    Senior Member Peritus's Avatar
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    you don't need to expand anything:


    \begin{gathered}<br />
  \left( {2x + 1} \right)^2  + x\left( {2 + 4x} \right) = 0 \hfill \\<br />
   \Leftrightarrow \left( {2x + 1} \right)^2  + 2x\left( {2x + 1} \right) = 0 \hfill \\<br />
   \Leftrightarrow \left( {2x + 1} \right)\left( {4x + 1} \right) = 0 \hfill \\ <br />
\end{gathered} <br />
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  3. #3
    Super Member
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    Quote Originally Posted by Peritus View Post
    you don't need to expand anything:


    \begin{gathered}<br />
\left( {2x + 1} \right)^2 + x\left( {2 + 4x} \right) = 0 \hfill \\<br />
\Leftrightarrow \left( {2x + 1} \right)^2 + 2x\left( {2x + 1} \right) = 0 \hfill \\<br />
\Leftrightarrow \left( {2x + 1} \right)\left( {4x + 1} \right) = 0 \hfill \\ <br />
\end{gathered} <br />
    yes yes i had it right, just made a silly mistake... thanks for that!
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