$\displaystyle (2x+1)^2 + x(2+4x) = 0$

then i expanded and collected like terms and got

$\displaystyle 8x^2+6x+1 = 0$

then i was having problems factorizing this expression.any help?

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- Oct 31st 2008, 11:33 PMjvignaciofactorizing
$\displaystyle (2x+1)^2 + x(2+4x) = 0$

then i expanded and collected like terms and got

$\displaystyle 8x^2+6x+1 = 0$

then i was having problems factorizing this expression.any help? - Nov 1st 2008, 12:17 AMPeritus
you don't need to expand anything:

$\displaystyle \begin{gathered}

\left( {2x + 1} \right)^2 + x\left( {2 + 4x} \right) = 0 \hfill \\

\Leftrightarrow \left( {2x + 1} \right)^2 + 2x\left( {2x + 1} \right) = 0 \hfill \\

\Leftrightarrow \left( {2x + 1} \right)\left( {4x + 1} \right) = 0 \hfill \\

\end{gathered}

$ - Nov 1st 2008, 12:24 AMjvignacio