# factorizing

• Nov 1st 2008, 12:33 AM
jvignacio
factorizing
$(2x+1)^2 + x(2+4x) = 0$

then i expanded and collected like terms and got

$8x^2+6x+1 = 0$

then i was having problems factorizing this expression.any help?
• Nov 1st 2008, 01:17 AM
Peritus
you don't need to expand anything:

$\begin{gathered}
\left( {2x + 1} \right)^2 + x\left( {2 + 4x} \right) = 0 \hfill \\
\Leftrightarrow \left( {2x + 1} \right)^2 + 2x\left( {2x + 1} \right) = 0 \hfill \\
\Leftrightarrow \left( {2x + 1} \right)\left( {4x + 1} \right) = 0 \hfill \\
\end{gathered}
$
• Nov 1st 2008, 01:24 AM
jvignacio
Quote:

Originally Posted by Peritus
you don't need to expand anything:

$\begin{gathered}
\left( {2x + 1} \right)^2 + x\left( {2 + 4x} \right) = 0 \hfill \\
\Leftrightarrow \left( {2x + 1} \right)^2 + 2x\left( {2x + 1} \right) = 0 \hfill \\
\Leftrightarrow \left( {2x + 1} \right)\left( {4x + 1} \right) = 0 \hfill \\
\end{gathered}
$

yes yes i had it right, just made a silly mistake... thanks for that!