hi guys, i tryed to solve this two equations using substitution but my x's ended up canceling out when trying to solve for x.
eq 1
eq 2
eq 3 (re-arranged eq 1)
sub eq 3 into eq 2
that leaves me with no x
any help much appreciated
hi guys, i tryed to solve this two equations using substitution but my x's ended up canceling out when trying to solve for x.
eq 1
eq 2
eq 3 (re-arranged eq 1)
sub eq 3 into eq 2
that leaves me with no x
any help much appreciated
After a little manipulation, we have the system:
Adding the two equations together yields , which is not true. Thus there are no solutions.
In the future, if the variable disappears and you end up with some bizarre statement [like -5=3 or 0=2 , etc.], then you can conclude that there is no solution.
Does this make sense?
--Chris
Hello, jvignacio!
Your work is correct!
Here's another approach . . .
I tried to solve this two equations using substitution
but my x's ended up canceling out when trying to solve for x.
Graphic solution: we want the intersection of the two lines.
We have two lines: one has y-intercept -7, the other has y-intercept 4.
Both have slope 3 . . . The lines are parallel.Code:| / |/ / 4* / /| / / | / ----/--+-/------ / |/ -7* /| / | |
Obviously, the line do not intersect.
Therefore, the system has no solution.