# Thread: Quick GRE math question, taking it tomorrow morning

1. ## Quick GRE math question, taking it tomorrow morning

So I was going through my 3rd practice exam and I just was wondering how to solve this:

A/B=153 A/C=51 A>0 is A bigger or is C bigger? There is always the chance it cannot be solved with the information given...but I feel like it can be solved and I just am not sure how.

Thanks!

2. Originally Posted by kmfield
So I was going through my 3rd practice exam and I just was wondering how to solve this:

A/B=153 A/C=51 A>0 is A bigger or is C bigger? There is always the chance it cannot be solved with the information given...but I feel like it can be solved and I just am not sure how.

Thanks!
From the second equation you get:

$\displaystyle \dfrac AC = 51~\implies~C=\dfrac A{51}$ that means C is 51 times smaller than A.

If and only if the question was: Is B bigger than C?

you have to transform the first equation too:

$\displaystyle \dfrac AB = 153~\implies~B=\dfrac A{153}$ that means B is 153 times smaller than A.

Now it is obvious that B < C.