1. ## Two questions

1) 4(y +3)= 6
I know you times 4 by Y and 3 but I don't know what to do after that.

2) x3 + x=37
has a solution between 3 and 4
use a trial and improvement method to find this solution
you must show all your working.

2. Originally Posted by jedsterg
1) 4(y +3)= 6
I know you times 4 by Y and 3 but I don't know what to do after that.

2) x3 + x=37
has a solution between 3 and 4
use a trial and improvement method to find this solution
you must show all your working.
1. $4(y+3) = 6$

$y+3 = \frac{6}{4}$

$y + 3 = \frac{3}{2}$

$y = \frac{3}{2} - 3$

$y = \frac{3}{2} - \frac{6}{2}$

$y = -\frac{3}{2}$.

3. Originally Posted by jedsterg
1) 4(y +3)= 6
I know you times 4 by Y and 3 but I don't know what to do after that.
4y + 12 = 6

4y = 6 - 12

4y = - 6

$y = \frac{-6}{4}$

$y = \frac{-3}{2}$