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Math Help - Two questions

  1. #1
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    Two questions

    1) 4(y +3)= 6
    I know you times 4 by Y and 3 but I don't know what to do after that.

    2) x3 + x=37
    has a solution between 3 and 4
    use a trial and improvement method to find this solution
    give your answers correct to 1 decimal place
    you must show all your working.
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  2. #2
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    Quote Originally Posted by jedsterg View Post
    1) 4(y +3)= 6
    I know you times 4 by Y and 3 but I don't know what to do after that.

    2) x3 + x=37
    has a solution between 3 and 4
    use a trial and improvement method to find this solution
    give your answers correct to 1 decimal place
    you must show all your working.
    1. 4(y+3) = 6

    y+3 = \frac{6}{4}

    y + 3 = \frac{3}{2}

    y = \frac{3}{2} - 3

    y = \frac{3}{2} - \frac{6}{2}

    y = -\frac{3}{2}.
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  3. #3
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    Quote Originally Posted by jedsterg View Post
    1) 4(y +3)= 6
    I know you times 4 by Y and 3 but I don't know what to do after that.
    4y + 12 = 6

    4y = 6 - 12

    4y = - 6

    y = \frac{-6}{4}

    y = \frac{-3}{2}
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