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Math Help - Babylonian Mathematics

  1. #1
    Junior Member mcdanielnc89's Avatar
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    Babylonian Mathematics

    Can anyone explain how to solve base 60 problems.

    All I know is my sister came home and asked. here's what she gave me.


    a*b=[(ab)(ab)]/4-[(a-b)(a-b)]/4



    Anyone make any sense out of it.
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  2. #2
    Junior Member mcdanielnc89's Avatar
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    anyone?
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  3. #3
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by mcdanielnc89 View Post
    Can anyone explain how to solve base 60 problems.

    All I know is my sister came home and asked. here's what she gave me.


    a*b=[(ab)(ab)]/4-[(a-b)(a-b)]/4



    Anyone make any sense out of it.
    Just expand it

    \frac{(a+b)^2}{4}-\frac{(a-b)^2}{4}=\frac{1}{4}\left((a+b)+(a-b)\right)\left((a+b)-(a-b)\right)=\frac{ab}{4}\cdot{4}=ab
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