Find the zeros of function

f(x) = x^2(2e^2x) + 2xe^2x + e^2x + 2xe^2x)

Attached is what I got. Is it correct?

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- Oct 30th 2008, 10:53 AMmwokFind zeroes of this function (difficult)
Find the zeros of function

f(x) = x^2(2e^2x) + 2xe^2x + e^2x + 2xe^2x)

Attached is what I got. Is it correct? - Oct 30th 2008, 11:01 AMChris L T521
- Oct 30th 2008, 11:15 AMmwok
Ahh, you have to take the commons out and then use the quad formula. Nice!

Question...I used the quad formula and ended up with

x = (-2 +/- sqrt(2)) / 2

Do I make it equal zero and then solve it further OR is that the direct zero?

Also, what about the other factor e^2x....how would you solve that for zero?

e^2x = 0

I'm guessing you have to use the log equation on that? - Oct 30th 2008, 11:18 AMChris L T521
- Oct 30th 2008, 11:20 AMmwok
- Oct 30th 2008, 11:24 AMChris L T521