Find three consecutive even integers such that twice the sum of the first and the third integers is twenty-one more than the second integer.
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Originally Posted by Ashiebug3 Find three consecutive even integers such that twice the sum of the first and the third integers is twenty-one more than the second integer. x,x+1,x+2 2(x+(x+2))=21+(x+1) 4x+4=x+22 3x=18 x=6 6,7,8
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