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  1. #1
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    solve

    Find three consecutive even integers such that twice the sum of the first and the third integers is twenty-one more than the second integer.
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  2. #2
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    Quote Originally Posted by Ashiebug3
    Find three consecutive even integers such that twice the sum of the first and the third integers is twenty-one more than the second integer.
    x,x+1,x+2

    2(x+(x+2))=21+(x+1)
    4x+4=x+22
    3x=18
    x=6

    6,7,8
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