Thread: solve

Find three consecutive even integers such that twice the sum of the first and the third integers is twenty-one more than the second integer.

Originally Posted by Ashiebug3

Find three consecutive even integers such that twice the sum of the first and the third integers is twenty-one more than the second integer.

x,x+1,x+2

2(x+(x+2))=21+(x+1)
4x+4=x+22
3x=18
x=6

6,7,8