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Math Help - Another math question....Kinda easy but confusing

  1. #1
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    Another math question....Kinda easy but confusing

    Ok heres another one. and no the other one hasnt been answered yet but heres a differen tone i dont get.

    In 30 years, Sue will be 4 times the age she is now. How old is she now?

    I no it seems easy but its weird to me :P im in mathcounts its like a advanced math thing for 7th grade but any help how to do it?
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  2. #2
    Newbie Melodare's Avatar
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    Quote Originally Posted by xsriel View Post
    Ok heres another one. and no the other one hasnt been answered yet but heres a differen tone i dont get.

    In 30 years, Sue will be 4 times the age she is now. How old is she now?

    I no it seems easy but its weird to me :P im in mathcounts its like a advanced math thing for 7th grade but any help how to do it?
    Well, I'm sure you've figured out that you need to write an equation.

    x = Sue's present age
    x + 30 = Sue's age 30 yrs from now.

    So the equation would be x + 30 = 4x.

    And you would solve for x, and get your answer.
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