1. ## Can't believe I'm asking this...

It has been a while since I've done algebra. I need to solve this equation in terms of L.

$\displaystyle (Kw)/(Ln)=(Nw)/(Lr)$

Note: N and n are different variables.

2. Haha ya same here ... I'll give it a shot but no guarentees

Equation:

(Kw)/(Ln) = (Nw)/(Lr)
[L^2r] (Kw)/(Ln) = (Nw)/(Lr) [L^2r]
gives us
(L^2Krw)/(L^3nr) = LNw
(L^2Krw)/L^3nr)/ [Nw] = (LNw)/ [Nw]
gives us
Kr/Lwr = L

Not sure if something can be given in terms of L with L being on both sides ... but that is the best I got for ya =D

3. Originally Posted by mcox05
Haha ya same here ... I'll give it a shot but no guarentees

Equation:

(Kw)/(Ln) = (Nw)/(Lr)
[L^2r] (Kw)/(Ln) = (Nw)/(Lr) [L^2r]
gives us
(L^2Krw)/(L^3nr) = LNw You can't use the rule of distribution here!
(L^2Krw)/L^3nr)/ [Nw] = (LNw)/ [Nw]
gives us
Kr/Lwr = L

Not sure if something can be given in terms of L with L being on both sides ... but that is the best I got for ya =D
This fraction ...... $\displaystyle \dfrac{Kw} {Ln}=\dfrac{Nw}{Lr}$ ...... simplifies to: ...... $\displaystyle \dfrac{K} {n}=\dfrac{N}{r}$

That means $\displaystyle L\in \mathbb{R}\setminus\{0\}$