It has been a while since I've done algebra. I need to solve this equation in terms of L.

$\displaystyle (Kw)/(Ln)=(Nw)/(Lr)$

Note: N and n are different variables.

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- Oct 29th 2008, 12:42 PM #1

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- Oct 30th 2008, 03:19 AM #2

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Haha ya same here ... I'll give it a shot but no guarentees

Equation:

(Kw)/(Ln) = (Nw)/(Lr)

[L^2r] (Kw)/(Ln) = (Nw)/(Lr) [L^2r]

gives us

(L^2Krw)/(L^3nr) = LNw

(L^2Krw)/L^3nr)/ [Nw] = (LNw)/ [Nw]

gives us

Kr/Lwr = L

Not sure if something can be given in terms of L with L being on both sides ... but that is the best I got for ya =D

- Oct 30th 2008, 06:23 AM #3

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