# Easy word problem has me stumped.

• Oct 28th 2008, 08:16 PM
Tomanator
Easy word problem has me stumped.
For the person responding, can you please explain the logic of how you set up the equation.

Thank anyone who responds in advance

Q) The sum of two numbers is 15. Three times one of the numbers is 11 less than five times the other. Find the numbers.

*from the back of the book, I already know that the answer is 6, 7,

What I put together was
3x=5x-11 but considering that there are two number to answer for, I realize I am wrong.
• Oct 29th 2008, 09:08 AM
enzzz
No, answer is not 6;7. How could 6+7 be 15?

Well.. you got one equation right ( 3x=5y-11 )

Since you have two variables you also need two equations. And the other one would be in the first sentence I wrote. (the sum of those two variables is 15).
So it is x+y=15.. Then you could write out X, which is x=15-y and then you could just replace it to the other equation. Rest should be easy enough.

3(15-y)=5y-11
45-3y=5y-11
8y=56
y=7..
And then..
x=15-7
• Oct 29th 2008, 11:38 AM
Tomanator
Thank you. Yes the I mis-wrote that it should be 7 and 8.