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Thread: Distributing negatives

  1. October 28th 2008, 06:05 PM #1
    realintegerz
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    Distributing negatives

    I've had problems with this for a while now...can someone please explain?





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  2. October 29th 2008, 09:04 AM #2
    masters
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    There are a number of ways you can distribute a negative over a rational expression. Here are a few of them.

    -\left(\frac{x^3-3}{x^2+1}\right)=\frac{-(x^3-3)}{x^2+1}=\frac{-x^3+3}{x^2+1}=\frac{3-x^3}{x^2+1}

    -\left(\frac{x^3-3}{x^2+1}\right)=\frac{x^3-3}{-(x^2+1)}=\frac{x^3-3}{-x^2-1}
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