(7X10^6)/(aX10^n) = 8.75X10^9 where a>=1 and a<10.

7X10^6 = aX10^n X 8.75X10^9

1/8.75 = aX10^(n+9-6)

0.8 = aX10^(n+3)

8/10 = aX10^(n+3)

8 = aX10^(n+3) X 10^1

8 = aX10^(n+3+1)

8 = aX10^(n+4)

a = 8/[10^(n+4)]

a>=1

8/[10^(n+4)]>=1

8>=10^(n+4)

log8>=log10^(n+4)

log8>=(n+4)log10

log8>=(n+4)(1) (since log10 =1)

log8>=n+4

log8-4>=n

-3.096910013>=n

or

a<10

8/[10^(n+4)]<10

8<10X10^(n+4)

8<10^(n+4+1)

8<10^(n+5)

log8<log10^(n+5)

log8<(n+5)log10

log8<(n+5)(1) (since log10 = 1)

log8<n+5

log8-5<n

0.4771212547<n

(I am not sure if the above solution is correct. It seems too involved. I feel that there might be an easier solution. I sure would like to know what it is. Cheers Abey.