how do you integrate dy/(y(1-y))?

I got ln|y| + 1/y

Printable View

- Oct 28th 2008, 02:57 PMUnt0tIntegrating help
how do you integrate dy/(y(1-y))?

I got ln|y| + 1/y - Oct 28th 2008, 03:07 PMHallsofIvy
Excellent! How did you get that? I would be inclined to use "partial fractions" writing as . But integrating that should involve a "ln(1-x)" and I don't see that in your answer.

- Oct 28th 2008, 03:16 PMUnt0t
lol I don't get it. Could you please show me how to work it out and give me the answear

- Oct 28th 2008, 03:37 PMUnt0t
I'll actually give you the full question and hopefully someone can help me.

dy/dt= y(1-y) and they want us to find the general solution... I know its a seperable equation so I get dy/(y(1-y)) = 1 dt and we're ment to integrate it... though I dont know how. And the answer they give is y(t)= ke^t/(ke^t +1) - Oct 28th 2008, 03:57 PMMathstud28

- Oct 28th 2008, 04:13 PMKrizalid