INTEGER SEQUENCES

**abey_27** · October 28th 2008, 12:40 PM

the nth term of a sequence is given by this formula:

nth term = 62 - 5n

Find an expressipn, in terms of n, for the sum of the nth term and (n+1)th term of the sequence. thanks

**Soroban** · October 28th 2008, 01:28 PM

Hello, abey_27!

It seems simple enough . . . Exactly where is your difficulty?

The $n^{th}$ term of a sequence is given by: . $a_n \:=\:62-5n$

Find an expression, in terms of $n$ ,
for the sum of the $n^{th}$ term and $(n+1)^{th}$ term of the sequence.

We have:. $\begin{array}{ccc}a_n &=& 62 - 5n \\<br /> a_{n+1} &=& 62-5(n\!+\!1) \end{array}$

Therefore: . $a_n + a_{n+1} \;=\;[62-5n] + [62-5(n+1)] \;=\;119 - 10n$

**abey_27** · October 28th 2008, 01:43 PM

i didnt really understand what it meant by 'sum of the nth term', so is that simply just the formula nth term= 62-5n ?

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