Thread: Solve Logarithm

I'm having the same kind of problems on all of the following problems: I cannot seem to isolate X. Help if you can!

1. 5^(x+1)=e^x
2. 3^(x+1)=(9^x)(27^(x+1))
3. 10^(2x+1)=4^(x+1)
4. 5^(3x-2)=3^(x+1)
5. *Log Base is 2* Log(x+4) + Log(x+2)=Log3

Much appreciated!

Originally Posted by ellimist121

1. 5^(x+1)=e^x

Take of both sides to get, . Using identities we get . But . Thus, we are left with . Rewrite as . Factor, . And this gives

2. 3^(x+1)=(9^x)(27^(x+1))

This is,

Now solve for

Try doing the other problems.

Thanks, but I'm still having trouble with the last one I have gotten to this:

Log(((x+4)(x+2))/3)=0

Also, with this one:

(5^2x)-7(5^x)+12=0.

Originally Posted by ellimist121

Thanks, but I'm still having trouble with the last one I have gotten to this:

Log(((x+4)(x+2))/3)=0

Also, with this one:

(5^2x)-7(5^x)+12=0.