# Thread: Probability question

1. ## Probability question

Two identical dice are thrown, one after the other. What are the probabilities that (i) the total of the numbers shown is 6, (ii) the second number is greater than the first? I got the answers 5/36 for the first part and 15/36 for the second. I think they are correct but to get the answer for part 1 I listed out the possible combinations of the two dice, and for part 2 I made a different list. Are there any other methods I could have used to arrive at the same answer?

2. Originally Posted by david18
Two identical dice are thrown, one after the other. What are the probabilities that (i) the total of the numbers shown is 6, (ii) the second number is greater than the first? I got the answers 5/36 for the first part and 15/36 for the second. I think they are correct but to get the answer for part 1 I listed out the possible combinations of the two dice, and for part 2 I made a different list. Are there any other methods I could have used to arrive at the same answer?
1) Well, yes, there are 36 (6*6) different possibilites of outcome while throwing the dice and to get the sum of 6 there are 5 chances (1 and 5; 2 and 4; 3 and 3; 4 and 2; 5 and 1). So 5/36 must be right.
2) Chances for that are ((5/6)+(4/6)+(3/6)+(2/6)+(1/6)+(0/6)) / 6=15/36
Average for each dice thrown.. Well this would be the way I would calculate although I'm not sure whether there is a better way.

3. Originally Posted by david18
Two identical dice are thrown, one after the other. What are the probabilities that (i) the total of the numbers shown is 6, (ii) the second number is greater than the first? I got the answers 5/36 for the first part and 15/36 for the second. I think they are correct but to get the answer for part 1 I listed out the possible combinations of the two dice, and for part 2 I made a different list. Are there any other methods I could have used to arrive at the same answer?
Personally I'd use a dice table. Eg. Dice table