hi guys have problems with this question
find real solutions for:
$\displaystyle
x^2 - 2x - 48 = 0
$
i tryed using quadratic but it ends up being a square root minus which is ERROR?
any help? cheers
The quadratic formula is unnecessary since $\displaystyle x^2 - 2x - 48 = (x - 8)(x + 6) \, ....$
Note: Without seeing your working it's impossible to know what mistake(s) you've made in applying the quadratic formula. At a guess, I'd say you found the discriminant to be either 4 - 4(48) = -188 or -4 - 4(48) = -196 ...... both are wrong. It's (-2)^2 - 4(-48) = 4 - 4(-48) = 196.