# Thread: find real solutions for equation

1. ## find real solutions for equation

hi guys have problems with this question
find real solutions for:

$\displaystyle x^2 - 2x - 48 = 0$

i tryed using quadratic but it ends up being a square root minus which is ERROR?

any help? cheers

2. Originally Posted by jvignacio
hi guys have problems with this question
find real solutions for:

$\displaystyle x^2 - 2x - 48 = 0$

i tryed using quadratic but it ends up being a square root minus which is ERROR?

any help? cheers
The quadratic formula is unnecessary since $\displaystyle x^2 - 2x - 48 = (x - 8)(x + 6) \, ....$

Note: Without seeing your working it's impossible to know what mistake(s) you've made in applying the quadratic formula. At a guess, I'd say you found the discriminant to be either 4 - 4(48) = -188 or -4 - 4(48) = -196 ...... both are wrong. It's (-2)^2 - 4(-48) = 4 - 4(-48) = 196.

3. Originally Posted by mr fantastic
The quadratic formula is unnecessary since $\displaystyle x^2 - 2x - 48 = (x - 8)(x + 6) \, ....$

Note: Without seeing your working it's impossible to know what mistake(s) you've made in applying the quadratic formula. At a guess, I'd say you found the discriminant to be either 4 - 4(48) = -188 or -4 - 4(48) = -196 ...... both are wrong. It's (-2)^2 - 4(-48) = 4 - 4(-48) = 196.
i get ya. so the answer would be

x = 8 , x = -6 ?

4. Originally Posted by jvignacio
i get ya. so the answer would be

x = 8 , x = -6 ?
Yes.