hi guys have problems with this question

find real solutions for:

$\displaystyle

x^2 - 2x - 48 = 0

$

i tryed using quadratic but it ends up being a square root minus which is ERROR?

any help? cheers

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- Oct 27th 2008, 04:16 AMjvignaciofind real solutions for equation
hi guys have problems with this question

find real solutions for:

$\displaystyle

x^2 - 2x - 48 = 0

$

i tryed using quadratic but it ends up being a square root minus which is ERROR?

any help? cheers - Oct 27th 2008, 04:25 AMmr fantastic
The quadratic formula is unnecessary since $\displaystyle x^2 - 2x - 48 = (x - 8)(x + 6) \, ....$

Note: Without seeing your working it's impossible to know what mistake(s) you've made in applying the quadratic formula. At a guess, I'd say you found the discriminant to be either 4 - 4(48) = -188 or -4 - 4(48) = -196 ...... both are wrong. It's (-2)^2 - 4(-48) = 4 - 4(-48) = 196. - Oct 27th 2008, 04:39 AMjvignacio
- Oct 27th 2008, 04:41 AMmr fantastic